Optimal. Leaf size=155 \[ -\frac {(i A+B) (a+i a \tan (e+f x))^{7/2}}{11 f (c-i c \tan (e+f x))^{11/2}}-\frac {(2 i A-9 B) (a+i a \tan (e+f x))^{7/2}}{99 c f (c-i c \tan (e+f x))^{9/2}}-\frac {(2 i A-9 B) (a+i a \tan (e+f x))^{7/2}}{693 c^2 f (c-i c \tan (e+f x))^{7/2}} \]
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Rubi [A]
time = 0.17, antiderivative size = 155, normalized size of antiderivative = 1.00, number of steps
used = 4, number of rules used = 4, integrand size = 45, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.089, Rules used = {3669, 79, 47,
37} \begin {gather*} -\frac {(-9 B+2 i A) (a+i a \tan (e+f x))^{7/2}}{693 c^2 f (c-i c \tan (e+f x))^{7/2}}-\frac {(-9 B+2 i A) (a+i a \tan (e+f x))^{7/2}}{99 c f (c-i c \tan (e+f x))^{9/2}}-\frac {(B+i A) (a+i a \tan (e+f x))^{7/2}}{11 f (c-i c \tan (e+f x))^{11/2}} \end {gather*}
Antiderivative was successfully verified.
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Rule 37
Rule 47
Rule 79
Rule 3669
Rubi steps
\begin {align*} \int \frac {(a+i a \tan (e+f x))^{7/2} (A+B \tan (e+f x))}{(c-i c \tan (e+f x))^{11/2}} \, dx &=\frac {(a c) \text {Subst}\left (\int \frac {(a+i a x)^{5/2} (A+B x)}{(c-i c x)^{13/2}} \, dx,x,\tan (e+f x)\right )}{f}\\ &=-\frac {(i A+B) (a+i a \tan (e+f x))^{7/2}}{11 f (c-i c \tan (e+f x))^{11/2}}+\frac {(a (2 A+9 i B)) \text {Subst}\left (\int \frac {(a+i a x)^{5/2}}{(c-i c x)^{11/2}} \, dx,x,\tan (e+f x)\right )}{11 f}\\ &=-\frac {(i A+B) (a+i a \tan (e+f x))^{7/2}}{11 f (c-i c \tan (e+f x))^{11/2}}-\frac {(2 i A-9 B) (a+i a \tan (e+f x))^{7/2}}{99 c f (c-i c \tan (e+f x))^{9/2}}+\frac {(a (2 A+9 i B)) \text {Subst}\left (\int \frac {(a+i a x)^{5/2}}{(c-i c x)^{9/2}} \, dx,x,\tan (e+f x)\right )}{99 c f}\\ &=-\frac {(i A+B) (a+i a \tan (e+f x))^{7/2}}{11 f (c-i c \tan (e+f x))^{11/2}}-\frac {(2 i A-9 B) (a+i a \tan (e+f x))^{7/2}}{99 c f (c-i c \tan (e+f x))^{9/2}}-\frac {(2 i A-9 B) (a+i a \tan (e+f x))^{7/2}}{693 c^2 f (c-i c \tan (e+f x))^{7/2}}\\ \end {align*}
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Mathematica [A]
time = 7.62, size = 135, normalized size = 0.87 \begin {gather*} \frac {a^3 \cos (e+f x) (-77 i A+9 (-9 i A+2 B) \cos (2 (e+f x))-9 (2 A+9 i B) \sin (2 (e+f x))) (\cos (9 e+12 f x)+i \sin (9 e+12 f x)) \sqrt {a+i a \tan (e+f x)} \sqrt {c-i c \tan (e+f x)}}{1386 c^6 f (\cos (f x)+i \sin (f x))^3} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.42, size = 161, normalized size = 1.04
method | result | size |
risch | \(-\frac {a^{3} \sqrt {\frac {a \,{\mathrm e}^{2 i \left (f x +e \right )}}{{\mathrm e}^{2 i \left (f x +e \right )}+1}}\, \left (63 i A \,{\mathrm e}^{10 i \left (f x +e \right )}+63 B \,{\mathrm e}^{10 i \left (f x +e \right )}+154 i A \,{\mathrm e}^{8 i \left (f x +e \right )}+99 i A \,{\mathrm e}^{6 i \left (f x +e \right )}-99 B \,{\mathrm e}^{6 i \left (f x +e \right )}\right )}{2772 c^{5} \sqrt {\frac {c}{{\mathrm e}^{2 i \left (f x +e \right )}+1}}\, f}\) | \(119\) |
derivativedivides | \(\frac {i \sqrt {a \left (1+i \tan \left (f x +e \right )\right )}\, \sqrt {-c \left (i \tan \left (f x +e \right )-1\right )}\, a^{3} \left (1+\tan ^{2}\left (f x +e \right )\right ) \left (2 i A \left (\tan ^{4}\left (f x +e \right )\right )-63 i B \left (\tan ^{3}\left (f x +e \right )\right )-9 B \left (\tan ^{4}\left (f x +e \right )\right )-45 i A \left (\tan ^{2}\left (f x +e \right )\right )-14 A \left (\tan ^{3}\left (f x +e \right )\right )+63 i B \tan \left (f x +e \right )-144 B \left (\tan ^{2}\left (f x +e \right )\right )+79 i A -140 A \tan \left (f x +e \right )-9 B \right )}{693 f \,c^{6} \left (i+\tan \left (f x +e \right )\right )^{7}}\) | \(161\) |
default | \(\frac {i \sqrt {a \left (1+i \tan \left (f x +e \right )\right )}\, \sqrt {-c \left (i \tan \left (f x +e \right )-1\right )}\, a^{3} \left (1+\tan ^{2}\left (f x +e \right )\right ) \left (2 i A \left (\tan ^{4}\left (f x +e \right )\right )-63 i B \left (\tan ^{3}\left (f x +e \right )\right )-9 B \left (\tan ^{4}\left (f x +e \right )\right )-45 i A \left (\tan ^{2}\left (f x +e \right )\right )-14 A \left (\tan ^{3}\left (f x +e \right )\right )+63 i B \tan \left (f x +e \right )-144 B \left (\tan ^{2}\left (f x +e \right )\right )+79 i A -140 A \tan \left (f x +e \right )-9 B \right )}{693 f \,c^{6} \left (i+\tan \left (f x +e \right )\right )^{7}}\) | \(161\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.67, size = 210, normalized size = 1.35 \begin {gather*} \frac {{\left (63 \, {\left (-i \, A - B\right )} a^{3} \cos \left (\frac {11}{2} \, \arctan \left (\sin \left (2 \, f x + 2 \, e\right ), \cos \left (2 \, f x + 2 \, e\right )\right )\right ) - 154 i \, A a^{3} \cos \left (\frac {9}{2} \, \arctan \left (\sin \left (2 \, f x + 2 \, e\right ), \cos \left (2 \, f x + 2 \, e\right )\right )\right ) + 99 \, {\left (-i \, A + B\right )} a^{3} \cos \left (\frac {7}{2} \, \arctan \left (\sin \left (2 \, f x + 2 \, e\right ), \cos \left (2 \, f x + 2 \, e\right )\right )\right ) + 63 \, {\left (A - i \, B\right )} a^{3} \sin \left (\frac {11}{2} \, \arctan \left (\sin \left (2 \, f x + 2 \, e\right ), \cos \left (2 \, f x + 2 \, e\right )\right )\right ) + 154 \, A a^{3} \sin \left (\frac {9}{2} \, \arctan \left (\sin \left (2 \, f x + 2 \, e\right ), \cos \left (2 \, f x + 2 \, e\right )\right )\right ) + 99 \, {\left (A + i \, B\right )} a^{3} \sin \left (\frac {7}{2} \, \arctan \left (\sin \left (2 \, f x + 2 \, e\right ), \cos \left (2 \, f x + 2 \, e\right )\right )\right )\right )} \sqrt {a}}{2772 \, c^{\frac {11}{2}} f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 3.14, size = 131, normalized size = 0.85 \begin {gather*} -\frac {{\left (63 \, {\left (i \, A + B\right )} a^{3} e^{\left (13 i \, f x + 13 i \, e\right )} + 7 \, {\left (31 i \, A + 9 \, B\right )} a^{3} e^{\left (11 i \, f x + 11 i \, e\right )} + 11 \, {\left (23 i \, A - 9 \, B\right )} a^{3} e^{\left (9 i \, f x + 9 i \, e\right )} + 99 \, {\left (i \, A - B\right )} a^{3} e^{\left (7 i \, f x + 7 i \, e\right )}\right )} \sqrt {\frac {a}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt {\frac {c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}}}{2772 \, c^{6} f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 11.75, size = 217, normalized size = 1.40 \begin {gather*} -\frac {a^3\,\sqrt {\frac {a\,\left (\cos \left (2\,e+2\,f\,x\right )+1+\sin \left (2\,e+2\,f\,x\right )\,1{}\mathrm {i}\right )}{\cos \left (2\,e+2\,f\,x\right )+1}}\,\left (A\,\cos \left (6\,e+6\,f\,x\right )\,99{}\mathrm {i}+A\,\cos \left (8\,e+8\,f\,x\right )\,154{}\mathrm {i}+A\,\cos \left (10\,e+10\,f\,x\right )\,63{}\mathrm {i}-99\,B\,\cos \left (6\,e+6\,f\,x\right )+63\,B\,\cos \left (10\,e+10\,f\,x\right )-99\,A\,\sin \left (6\,e+6\,f\,x\right )-154\,A\,\sin \left (8\,e+8\,f\,x\right )-63\,A\,\sin \left (10\,e+10\,f\,x\right )-B\,\sin \left (6\,e+6\,f\,x\right )\,99{}\mathrm {i}+B\,\sin \left (10\,e+10\,f\,x\right )\,63{}\mathrm {i}\right )}{2772\,c^5\,f\,\sqrt {\frac {c\,\left (\cos \left (2\,e+2\,f\,x\right )+1-\sin \left (2\,e+2\,f\,x\right )\,1{}\mathrm {i}\right )}{\cos \left (2\,e+2\,f\,x\right )+1}}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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